Chemistry, asked by prajapativaibhav000, 8 months ago

how to find acid strength in conjugate acid ​

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Answered by mahira15
1

Answer:

Subtract "1" from the total number of hydrogen atoms. For example, if sulfuric acid has two hydrogens, then its conjugate base will have only one hydrogen atom. Add "-1" to the molecule's total charge. So, if the acid hydrogen sulfate has a charge of "-1," its conjugate base will have a charge of "-2."

Explanation:

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Answered by Anonymous
3

HERE IS YOUR ANSWER..

A conjugate acid contains one more H atom and one more + charge than the base that formed it.

A conjugate acid contains one more H atom and one more + charge than the base that formed it.A conjugate base contains one less H atom and one more - charge than the acid that formed it.

A conjugate acid contains one more H atom and one more + charge than the base that formed it.A conjugate base contains one less H atom and one more - charge than the acid that formed it.Let us take the example of bicarbonate ions reacting with water to create carbonic acid and hydronium ions.

A conjugate acid contains one more H atom and one more + charge than the base that formed it.A conjugate base contains one less H atom and one more - charge than the acid that formed it.Let us take the example of bicarbonate ions reacting with water to create carbonic acid and hydronium ions.HCO₃⁻ + H₂O → H₂CO₃ + OH⁻

A conjugate acid contains one more H atom and one more + charge than the base that formed it.A conjugate base contains one less H atom and one more - charge than the acid that formed it.Let us take the example of bicarbonate ions reacting with water to create carbonic acid and hydronium ions.HCO₃⁻ + H₂O → H₂CO₃ + OH⁻base + acid → Conj A + Conj B

A conjugate acid contains one more H atom and one more + charge than the base that formed it.A conjugate base contains one less H atom and one more - charge than the acid that formed it.Let us take the example of bicarbonate ions reacting with water to create carbonic acid and hydronium ions.HCO₃⁻ + H₂O → H₂CO₃ + OH⁻base + acid → Conj A + Conj BWe see that HCO₃⁻ becomes H₂CO₃. It has one more H atom and one more + charge (-1 + 1 = 0). So H₂CO₃ is the conjugate acid of HCO₃⁻.

The H₂O becomes OH⁻. It has one less H atom and one more – charge. So OH⁻ is the conjugate base of H₂O.

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