Question

How to find angle when there are 2 unknown to the triangle​

Answer 1

Explanation:

The sum of all triangles in a triangle: $180^{0}$

let us assume that,

one of the angle is 'x'

and the second angle is twice of the first angle that is: 2x

the third angle: $60^{0}$

so,

the sum of all angles=$180^{0}$

which is equal to: $60^{0} +x+2x = 180^{0}$

then,

$60^{0} + 3x = 180^{0}$

Transpose $60^{0}$ from L.H.S to R.H.S

We get,

$3x = 180^{0}-60^{0} \\3x = 120^{}$

Transpose 3 from L.H.S to R.H.S

We get,

$x = \frac{120}{3}\\ x = 40^{0}$

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Thanking you,

Abhiram Sriman,

7th, Hyd