how to find area of isosceles triangle with perimeter?
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a,b and c are the sides of isosceles triangle two sides are equal in isosceles triangle
∴ a=b
semi perimeter = a+b+c+/2 =a+b+c/2 =2a+c/2
area of isosceles triangle
=√s(s-a)(s-a)(s-c)
∴ a=b
semi perimeter = a+b+c+/2 =a+b+c/2 =2a+c/2
area of isosceles triangle
=√s(s-a)(s-a)(s-c)
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