how to find area of rhombus while they have given like d¹ = 4/5 ft and d² = 1/3 ft
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Step-by-step explanation:
In pure water or a neutral solution the [H + ] = 1.0 × 10 -7 M. Substituting into the pH expression:
pH = -log[1.0 × 10 -7 ] = -(-7.00) = 7.00
The pH of pure water or any neutral solution is thus 7.00. For recording purposes, the numbers to the right of the decimal point in the pH value are the significant figures. Since 1.0 × 10 -7 has two significant figures, the pH can be reported as 7.00
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