Math, asked by riyana99, 1 year ago

how to find area to using sin and cos


sprightlyflutters: area of what...? triangle?
riyana99: Triangle
riyana99: Plz answering

Answers

Answered by manamperi344
1

In a triangle ABC , given two side lengths BC = a and AC =b and given also the angle between these two sides C, the area is given by:

Area = 0.5absin(C).


riyana99: Using in sine and cose
manamperi344: cos is not necessary here
riyana99: Ok, but sine is neccesary to here
manamperi344: Unless the correct angle isn't given, in which case you would have to find it maybe using sin/cos etc
riyana99: Ok
manamperi344: If you give me an example of a triangle then I can tell you exactly what to do, otherwise this is the formula
riyana99: Thanks to to giving more information
riyana99: I will try
riyana99: triangle ABC, AB=10cm, ANGLE A=55, ANGLE C = 70
manamperi344: In this case we must first compute length BC using the sine rule. Then also compute angle B (angles add up to 180). Now we can use the formula with the lengths AB and BC and the angle between them angle B so Area = 0.5 x AB x BC x sin(B).
Answered by YASHWANTH77
0
Area =0.5sinABcos if area is lb
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