Question

how to find centre and radius of circle if x=3-4sin and y=2-4cos​

Answer 1

Answer:

Center = (3,2)

Radius = 4

Step-by-step explanation:

x = 3-4sinΘ

y = 2-4cosΘ

$\text{We know that } \cos^2\theta + \sin^2 \theta = 1$

$\displaystyle \sin\theta = \frac{3-x}{4} \text{ and } \cos\theta = \frac{2-y}{4}$

$\displaystyle \left(\frac{3-x}{4} \right)^2 + \left(\frac{2-y}{4} \right)^2 = 1$

$\displaystyle (3-x)^2 + (2-y)^2 = 4^2$

Therefore, center = (3,2) and radius = 4