How to find common tangent of two parabolas?
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Answer:
y2=4x has a tangent y=mx+1m
Which is also tangent to x2=4y so this tangent passes through x2=4y
⇒x2=4(mx+1m)
x2−4mx−4m=0
Roots of this equation is same as their is one tangent hence
B2=4AC
(−4m)2=4×1×−4m
16m2=−−16m
m3=−1
Hence m=−1
Equation of tangent y=−x−1
x+y=−1
Step-by-step explanation:
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