How to find coordination number and oxidation state?
Answers
Answered by
0
Platinum is bonded with two types of ligands,
Ethylenediamine which is bidentate ligand is of two in number hence 2X2 =4
Chloride which is an unindented ligand is of two in number hence 1 X 2 = 2
Hence co-ordination number of Platinum will be 4 + 2 = 6
Oxidation state of Pt:
Charge on complex = 0
Hence, [x + (0 X 2) + ( -1 X 2)] = 0
x + 0 -2 = 0
x = 2
Hence oxidation state of Pt in the complex is +2
hope it help
mark as brainliest
Ethylenediamine which is bidentate ligand is of two in number hence 2X2 =4
Chloride which is an unindented ligand is of two in number hence 1 X 2 = 2
Hence co-ordination number of Platinum will be 4 + 2 = 6
Oxidation state of Pt:
Charge on complex = 0
Hence, [x + (0 X 2) + ( -1 X 2)] = 0
x + 0 -2 = 0
x = 2
Hence oxidation state of Pt in the complex is +2
hope it help
mark as brainliest
Similar questions