How to find current in unbalanced wheatstone bridge by using kirchoffs law
Answers
Answer:
The result of swapping the two resistors is that both sides or “arms” of the parallel network are different as they produce different voltage drops. When this happens the parallel network is said to be unbalanced as the voltage at point C is at a different value to the voltage at point D.
Answer:
Kirchhoff's first law (junction rule) - In an electrical circuit , the algebraic sum of currents meeting at a junction , is always zero .
Kirchhoff's second rule (loop rule) - In any closed mesh of an electrical circuit , the algebraic sum of the e.m.fs. is equal to the algebraic sum of products of resistances and current flowing through them .
Wheatstone bridge (balanced) - Let be the current from battery .At point A , current flows through resistance and current flows through . In balanced state , no current flows through BD , hence point B and D are at same potential .Therefore current flows through resistance also and current flows through .