How to find degree of quotient, q(x) and remainder, r(x) when degree of dividend, f(x) = 3 and degree of divisor, g(x) = 2. Find q(x) and r(x).
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as we know
f(x)=g(x)×q(x)+r(x)
if deg of f(x)=3
and deg of g(x)=2
:. deg of q(x) must be 1 so that g(x)×q(x)=3 and deg of r(x) can be 0
but less than deg of q(x)
f(x)=g(x)×q(x)+r(x)
if deg of f(x)=3
and deg of g(x)=2
:. deg of q(x) must be 1 so that g(x)×q(x)=3 and deg of r(x) can be 0
but less than deg of q(x)
luciferxixo:
since g(x) is the divisor, shouldn't r(x) < g(x)?
And as you said g(x) x q(x) = 3, how? Is it g(x)+q(x) ??
do u know the property dividend= divisor× quotient+remainder
Yes i do
then deg of f(x)=deg(x) +deg r(x)
deg f(x) =deg g(x)×deg q(x) +r(x)
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