Question

how to find dy/dy..​

Answer 1

Answer:

hope this will help you.

Answer 2

★given:-

$\implies \green{y = ae {}^{x} + b }$

★find:-

$\implies \pink{\frac{dy}{dx} }$

★solution:-

• given fuction differenciation with response x

$\implies \pink{ \frac{dy}{dx} = \frac{d}{dx}(ae {}^{x}) + \frac{d}{dx}(b)}$

we know that

• constant term differenciation zero so b differenciation zero

we know that formula of differenciation

$\implies \star \pink{\frac{d}{dx}u.v = u \frac{d}{dx} v + v \frac{d}{dx}u }$

let's

$\star \purple{u = a} \\ \: \star \purple{v = e {}^{x} }$

$\implies \pink{ \frac{dy}{dx} = \frac{d}{dx}(ae {}^{x}) +0 } \\ \\ \\ \implies \star \pink{ a\frac{d}{dx}e {}^{x} + e {}^{x} \frac{d}{dx} (a) }$

we know that differciation of

$\implies \star \: \frac{d}{dx} e {}^{x} = e {}^{x}$

a constant so a differenciation zero

$\implies \pink{ \frac{dy}{dx} = ae {}^{x}+0 } \\ \\ \\ \implies \star \pink{ \frac{dy}{dx} = ae {}^{x} }$

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I hope it helps you✔️