How to find electric field untensity at the centre of square?
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Explanation:
I assume the midpoint mentioned in the question means midpoint of the side of the square.
As shown in figure, distance between centre of square and corner of square is a/√2, where a is side of square.
Distance between midpoint of the side and centre of square is a/2.
E1 = 2q/ [(4πε0)a2] and E2 = 4q/ [(4πε0)a2]; hence E1/E2 = 1/2
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