How to find electronic configuration of elements 2n2?
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By putting n=1,2,3,4......... in the formula 2n2.
Like for n=1
=2×(1)^2=2
for n=2
=2×(2)^2=8
and for n=3
=2×(3)^2 =18......
Like for n=1
=2×(1)^2=2
for n=2
=2×(2)^2=8
and for n=3
=2×(3)^2 =18......
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