Question

how to find factarisation of 6x2_54

Answer 1

Answer:

$6 {x}^{2} - 54 = 6(x - 3)(x + 3)$

Step-by-step explanation:

To factorise the given polynomial,

firstly analyze that is there any common term in both the expression,

after than find that is the term belongs to some identity;

Here the term is

$6 {x}^{2} - 54 \\ \\ \implies6( {x}^{2} - 9) \\ \\ \implies6 \: ( {x}^{2} - {(3)}^{2} ) \\ \\ we \: know \: that \\ \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ \\ so \\ \\ \implies6(x - 3)(x + 3) \\ \\ 6 {x}^{2} - 54 = 6(x - 3)(x + 3)$

Hope it helps you.

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

FORMULA TO BE IMPLEMENTED

We are aware of the identity that

$\sf{ {a}^{2} - {b}^{2} \: = (a + b)(a - b) \: }$

TO DETERMINE

To Factorise

$\sf{6 {x}^{2} - 54}$

CALCULATION

$\sf{6 {x}^{2} - 54}$

$= \sf{6( {x}^{2} - 9})$

$= \sf{6 \{ {(x)}^{2} - {(3)}^{2} } \}$

$= \sf{2 \times 3 \times (x + 3)(x - 3)}$

RESULT

$\boxed{ \: \: \sf{6 {x}^{2} - 54} = \: 2 \times 3 \times (x + 3)(x - 3)\: }$

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