how to find factor of 224?
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224 is a composite number.
Prime factorization: 224 = 2 x 2 x 2 x 2 x 2 x 7, which can be written 224 = 2⁵ x 7
The exponents in the prime factorization are 5 and 1. Adding one to each and multiplying we get (5 + 1)(1 + 1) = 6 x 2 = 12. Therefore 224 has 12 factors.
Factors of 224: 1, 2, 4, 7, 8, 14, 16, 28, 32, 56, 112, 224
Factor pairs: 224 = 1 x 224, 2 x 112, 4 x 56, 7 x 32, 8 x 28, or 14 x 16
Taking the factor pair with the largest square number factor, we get √224 = (√16)( √14) = 4√14 ≈ 14.967
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prime factorisation
![224 \div 2 = 112 \\ \\ 112 \div 2 = 56 \\ \\ 56 \div 2 = 28 \\ \\ 28 \div 2 = 14 \\ \\ 14 \div 2 =7 \\ \\ 7 \div 7 = 1 \\ \\ these \: are \: the \: answers \: \: \\ 112 \\ 2 \\ 56 \\ 4 \\ 28 \\ 8 \\ 14 \\ 16 \\ 7 \\ 32 \\ 1 224 \div 2 = 112 \\ \\ 112 \div 2 = 56 \\ \\ 56 \div 2 = 28 \\ \\ 28 \div 2 = 14 \\ \\ 14 \div 2 =7 \\ \\ 7 \div 7 = 1 \\ \\ these \: are \: the \: answers \: \: \\ 112 \\ 2 \\ 56 \\ 4 \\ 28 \\ 8 \\ 14 \\ 16 \\ 7 \\ 32 \\ 1](https://tex.z-dn.net/?f=224+%5Cdiv+2+%3D+112+%5C%5C++%5C%5C+112+%5Cdiv+2+%3D+56+%5C%5C++%5C%5C+56+%5Cdiv+2+%3D+28+%5C%5C++%5C%5C+28+%5Cdiv+2+%3D+14+%5C%5C++%5C%5C+14+%5Cdiv+2+%3D7+%5C%5C++%5C%5C+++7+%5Cdiv+7+%3D+1+%5C%5C++%5C%5C++these++%5C%3A+are+%5C%3A+the+%5C%3A+answers+%5C%3A++%5C%3A++%5C%5C+112++%5C%5C+2+%5C%5C+56+%5C%5C+4+%5C%5C+28+%5C%5C+8+%5C%5C+14+%5C%5C+16+%5C%5C+7+%5C%5C+32+%5C%5C+1)
These are the answers and to do....
These are the answers and to do....
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