How to find hcf for 106 159 265
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❤❤❤hay...❤❤❤
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here given no are
106 , 159 ,265
now .....
prime factorisation of
these no...
106 = 53 × 2
159 =53×3
265= 53×5
hence HCF
= 53 ×2×3×5
= 106×3×5
=530×3
= 1590
SO.....
HCF is 1590
it is answer
➖➖➖➖➖➖➖
✔✔✔✔✔✔✔✔
plzz mark it as brainlist
⚓⚓⚓⚓⚓⚓⚓⚓
here given no are
106 , 159 ,265
now .....
prime factorisation of
these no...
106 = 53 × 2
159 =53×3
265= 53×5
hence HCF
= 53 ×2×3×5
= 106×3×5
=530×3
= 1590
SO.....
HCF is 1590
it is answer
➖➖➖➖➖➖➖
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