how to find height of isosceles triangle whose perimeter and base is given.
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example
By using the Pythagoras theorem
Explanation:
Draw the triangle first, The height is 15 and base is 16. Cut the triangle in half and you will end up with two triangles with a height of 15 and base of 8. Use the Pythagoras theorem and get the slant height. a2=b2+c2 By using this equation you will find the slant height
x2=152+82 simplify this and you will get 17 dm. perimeter=17+16+17=50dm
By using the Pythagoras theorem
Explanation:
Draw the triangle first, The height is 15 and base is 16. Cut the triangle in half and you will end up with two triangles with a height of 15 and base of 8. Use the Pythagoras theorem and get the slant height. a2=b2+c2 By using this equation you will find the slant height
x2=152+82 simplify this and you will get 17 dm. perimeter=17+16+17=50dm
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