How to find least count of an instrument? With example.
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Least count of vernier caliper...
Least count = 1 main scale division - 1 vernier scale division
Now, we know
10 divisions in main scale = 1cm
1 division in main scale( 1 MSD) = 1/10 = 0.1 cm
10 division in vernier scale = 9 division on main scale
1 division in vernier scale(1 VSD) = 9/10 division on main scale(MSD)
Least count = 1 MSD - 1 VSD = (1–9/10) MSD
Least count = 1/10 MSD = 0.1 × 0.1 = 0.01 cm
Least count = 0.01 cm (ans)
hope it helps you......
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