how to find
linear speed of mercury planet around the sun
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This allows us to determine how much longer and/or shorter the orbital periods of certain planets are, and how much smaller and/or larger their corresponding angular velocities are.
For example,
aEarthaMars≈15.0×1010m≈22.8×1010m
so
TMars≈(22.8×1010m15.0×1010m)3/2(1yr)≈1.87yr
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by Newonian mechanics
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