how to find log for "e power -2.079" ??
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1
Answer:
( - 2.079)
Step-by-step explanation:
We know that
log e= 1
&
log m^ n = n×log m
for example
log e³ = 3 log e
=> 3
Here,
log { e ^ (-2.079) } = (-2.079) × log e
=> (-2.079) Answer
Hope it helps...
:-)
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