Question

How to find mean median and mode for grouped data in statistics?

Answer 1

this is the example
To find the Mean Alex adds up all the numbers, then divides by how many numbers:

Mean = 59+65+61+62+53+55+60+70+64+56+58+58+62+62+68+65+56+59+68+61+6721
 = 61.38095...

 

To find the Median Alex places the numbers in value order and finds the middle number.



In this case the median is the 11th number:

53, 55, 56, 56, 58, 58, 59, 59, 60, 61, 61, 62, 62, 62, 64, 65, 65, 67, 68, 68, 70

Median = 61 

To find the Mode, or modal value, Alex places the numbers in value order then counts how many of each number. The Mode is the number which appears most often (there can be more than one mode):

53, 55, 56, 56, 58, 58, 59, 59, 60, 61, 61, 62, 62, 62, 64, 65, 65, 67, 68, 68, 70

62 appears three times, more often than the other values, so Mode = 62

Answer 2

$\huge\boxed{\underline{\underline{\purple{\mathfrak{Answer}}}}}$

$take \: the \: \frac{n}{2} th \: term \\ \frac{ \frac{n}{2} + cf }{f} \times h \\ where \: n = total\: of \: all \: frequency \\ cf = cumiliative \: frequency \\ f = frequency \\ and \: h = class \: interval$

$to \: find \: mode \: use \: this \: formula \\ \frac{l + (f1 - f0)}{(2 \times f0) - f1 - f2} \times h \\ where \: l = lower \: class \: limit \\ f2 = next \: class \: frequeny \\ f0 = frequency \\ f1 =preceding \: class \: frequency \\ and \: h \: = class \: interval$

$<marquee direction="left">$ follow the above mentioned steps^_^