Question

How to find min wavelength for Balmer series

Answer 1

Answer:

1026 A°

Explanation:

1/∆= R (1-1/9)

1/∆=R 8/9

∆=9/8R

∆=9/8×1/R

∆=9/8× 912

∆ = 9×114

∆ = 1026A°

This is explanation thank you