How to find n and Sn
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vbadithyan:
any one please
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Given that
a = 5, d = 3 and an = 50
So we know that
an = a+(n-1)d [ nth term of AP ]
⇒ 50 = 5+(n-1)3 [ Given ]
⇒ 50 = 5+3n-3
⇒ 50 = 3n+2
⇒ 3n = 48
⇒ n = 16
And
Sn = n/2[a+an] { Sum of AP ]
⇒ Sn =16/2[5+50}
⇒ Sn = 8(55)
⇒ Sn = 440
Hence number of terms = 16 and sum = 440.
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