Question

How to find n value in 2^2n-1=1/8^n-3 find tha value of n?

Answer 1

Answer:

The answer is in the attached file

Step-by-step explanation:

Answer 2

Answer:

The value of n is 2

Step-by-step explanation:

Given the expression

$2^{2n-1}=(\frac{1}{8^{n-3}})$

we have to find the value of n.

$2^{2n-1}=(\frac{1}{8^{n-3}})\\\\2^{2n-1}\times 8^{n-3}=1\\\\2^{2n-1}\times (2^3)^{n-3}=1\\\\2^{2n-1}\times 2^{3n-9}=1\\\\\text{As }x^a\times x^b=x^{a+b}\\\\2^{(2n-1+3n-9)}=2^0\\\\2^{5n-10}=2^0\\\text{Comparing both sides }\\5n-10=0\\5n=10\\n=\frac{10}{5}=2$

Hence, the value of n is 2