How to find numbers between 100 and 200 which is divisible by 3?
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First no. which is divisible by 3 after 100
is 102 and before 200 is 198
So it is an AP
102,105,108,........................,198
So formula to find total no.
An = a+(n-1)d
Here, An=198 a=102 d=105-102 = 3
198 = 102+(n-1)3
198-102=(n-1)3
96/3=n-1
32+1=n
n=33
So no. between 100 & 200 which are divisible by 3 are 33
is 102 and before 200 is 198
So it is an AP
102,105,108,........................,198
So formula to find total no.
An = a+(n-1)d
Here, An=198 a=102 d=105-102 = 3
198 = 102+(n-1)3
198-102=(n-1)3
96/3=n-1
32+1=n
n=33
So no. between 100 & 200 which are divisible by 3 are 33
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