Chemistry, asked by lakshmankommineni, 1 year ago

How to find order of heat of combustion in organic compounds ?​

Answers

Answered by shine0520
0

Hey mate....

Here's your answer....

For isomers differences in the heat of combustion are due to differences in the internal energy of the educts. If intermolecular interaction (lattice energy etc.) can be neglected it reflects differences in the internal energy of the molecules.

For isomers differences in the heat of combustion are due to differences in the internal energy of the educts. If intermolecular interaction (lattice energy etc.) can be neglected it reflects differences in the internal energy of the molecules.In your first example C has the smallest heat of combustion since it has the lowest internal Van der Waals strain.

For isomers differences in the heat of combustion are due to differences in the internal energy of the educts. If intermolecular interaction (lattice energy etc.) can be neglected it reflects differences in the internal energy of the molecules.In your first example C has the smallest heat of combustion since it has the lowest internal Van der Waals strain.In the second example the order is given by the ring strain, and the Van der Waals strain between the two methyl groups at the cyclobutane ring.

Hope this will be helpful to you mate......

Answered by sharavanakumar0987
0

Answer:

The molar heat of combustion (He) is the heat released when one mole of a substance is completely burned. In this case, one mole of oxygen reacts with one mole of methanol to form one mole of carbon dioxide and two moles of water. ... By measuring the temperature change, the heat of combustion can be determined

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