Question

how to find out d pi p pi bond

Answer 1

✨✨Hey...... Frnd here your answer
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Answer 2

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Answer:-

Lone pairs= (1/2)×(valence electrons - bonding electrons)

σ bonds= no. of surrounding atoms

π bonds= (no. of oxygen atoms) - (no. of negative charge)

Hybridization = σ bonds + no. of lone pairs

Now, no. of pπ-pπ bonds= no. of unhybridised p orbitals left

pπ-dπ bonds will be formed when π bonds are more than the no. of unhybridised p orbitals left. First pπ-pπ bonds are formed after that pπ-dπ if there are not enough p orbitals left for mutiple bond formation.

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