How to Find out Hybridisation of [Cr(H2O)6]3+
Answers
Answered by
25
cr =3d5,4s1 cr+3= 3d3,4s0 two vaccant d orbital available .so, d2sp3 irrespective of any ligand.
Answered by
29
Hey dear,
You can find out hybridization of compounds using molecular orbital theory.
● Answer -
[Cr(H2O)6]3+ shows d2sp3 hybridization.
● Explanation -
[Refer to the image for better understanding.]
Electronic configuration of Cr (Z=24) is [Ar] 3d5 4s1.
Cr loses 3e- to form Cr3+ with electronic configuration [Ar] 3d3 4s0.
Electrons from 6 water molecules fill two 3d, one 4s and three 4p orbitals.
Thus, [Cr(H2O)6]3+ shows d2sp3 hybridization.
Hope this helps you...
You can find out hybridization of compounds using molecular orbital theory.
● Answer -
[Cr(H2O)6]3+ shows d2sp3 hybridization.
● Explanation -
[Refer to the image for better understanding.]
Electronic configuration of Cr (Z=24) is [Ar] 3d5 4s1.
Cr loses 3e- to form Cr3+ with electronic configuration [Ar] 3d3 4s0.
Electrons from 6 water molecules fill two 3d, one 4s and three 4p orbitals.
Thus, [Cr(H2O)6]3+ shows d2sp3 hybridization.
Hope this helps you...
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