Question

how to find oxidation no. of a given element in a compound if the answer in coming in fractions.
for example Na2S4O6
it is coming +5/2 =2.5 but what to do for correct oxidation no.

Answer 1

Answer:

$2.5$

Explanation:

Na2S4O6

1×2 + 4x + (-2) × 6 = 0

2 + 4x - 12 = 0

4x = 10

x = + 2.5

Oxidation number of -

Na = 1

O = - 2

Here, The oxidation number of Sulphur is + 2.5

Here + 2.5 is the Correct Oxidation number , it matter that the oxidation number of any atom is coming in fraction or whole number.