how to find oxidation no. of coordination compound
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The oxidation number, or oxidation state, of an atom is the charge that would exist on the atom if the bonding were completely ionic. This oxidation number is an indicator of the degree of oxidation (loss of electrons) of an atom in a chemical compound. Conceptually, the oxidation state, which may be positive, negative or zero, is the hypothetical charge that an atom would have if all bonds to atoms of different elements were 100% ionic, with no covalent component. Oxidation number are typically represented by small integers.
In simple ions, the oxidation number of the atom is the charge on the ion. For example, Na+, K+, and H+ all have oxidation numbers of +1. O2- and S2- have oxidation numbers of -2. In a molecule or compound, the oxidation number is the sum of the oxidation numbers of its constituent atoms.
Example: What is the oxidation number of C2H6 ?
and answer is
The oxidation number of C is -3. The oxidation number of H is +1 (H+ has an oxidation number of +1). For the compound, we calculate the oxidation number as follows: 2(-3) + 6(+1) = 0. Therefore, the oxidation number of C2H6 is 0.
The oxidation number, or oxidation state, of an atom is the charge that would exist on the atom if the bonding were completely ionic. This oxidation number is an indicator of the degree of oxidation (loss of electrons) of an atom in a chemical compound. Conceptually, the oxidation state, which may be positive, negative or zero, is the hypothetical charge that an atom would have if all bonds to atoms of different elements were 100% ionic, with no covalent component. Oxidation number are typically represented by small integers.
In simple ions, the oxidation number of the atom is the charge on the ion. For example, Na+, K+, and H+ all have oxidation numbers of +1. O2- and S2- have oxidation numbers of -2. In a molecule or compound, the oxidation number is the sum of the oxidation numbers of its constituent atoms.
Example: What is the oxidation number of C2H6 ?
and answer is
The oxidation number of C is -3. The oxidation number of H is +1 (H+ has an oxidation number of +1). For the compound, we calculate the oxidation number as follows: 2(-3) + 6(+1) = 0. Therefore, the oxidation number of C2H6 is 0.
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