how to find oxidation number?
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Answered by
1
oxidation number for an atom in its elemental state is zero
oxidation of monovalent atom=charge of the monoatomic ion
1A=+1
2A=+2
3A=+3
4A=+4
5A=-3
6A=-2
7A=-1
8A=0
oxidation of monovalent atom=charge of the monoatomic ion
1A=+1
2A=+2
3A=+3
4A=+4
5A=-3
6A=-2
7A=-1
8A=0
Answered by
3
The sum of the oxidation states of all the atoms in an ion is equal to the charge on the ion.
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