Chemistry, asked by amritstar, 1 year ago

How to find oxidation number?

Explain all cases with example.

Answers

Answered by Anonymous
4
Rules for assiging oxidation number

✴️ The oxidation number of an element in its elementary form is 0 . for example, H2, P4, S8, Fe and Ag have oxidation number zero.

✴️ The oxidation number of an element in single ion is the charge on the ion, e.g.....K+ has oxidation number +1, Ca2+ has +2, Al3+ has +3 ans Cl- has - 1.

✴️ Hydrogen is assigned to oxidation number +1 and oxygen is assigned to oxidation number - 2 in almost all the compounds except in peroxide, the oxidation number of oxygen is - 1,in superoxide, it is - 1/2,whereas in O2f2 and OF2 it is +1 & +2. In NaoH, CaH2, KH, MgH2, LiH, the oxidation number of H is - 1.

✴️ Flourine has oxidation number - 1 except in HOF in which it is +1 but in exist only at - 40°C. Halogen compounds, e.g. in IF7, I has +7 oxidation number.

✴️ The oxidation number of alkali metals is +1 and alkaline earth metal have +2 in all of their compounds.

✴️ The algebraic sum of oxidation number of all the atoms ⚛ in a natural compound is zero. if it is ion, the algebraic sum is equal to charge on the ion.

✴️ In most of the cases, oxidation number is equal to oxidation state but not in all cases. Oxidation state cannot be in fraction or 0,,,
e. g, in Pb3O4, average oxidation number of Pb=+8/3,,whereas oxidation state is +2 nd +4 . in CrO5, oxidation number of Cr is +10,whereas oxidation state is +6 as there are two peroxide linkage in which four oxygen atom have - 1z oxidation state.

Anonymous: iski koi aavashyakta nhi.
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