Question

How to find oxidation state of oxygen in na2o2?

Answer 1

⭐《QUESTION》

↗To find the oxidation sate of Oxygen in Na2O2 ?

⭐《ANSWER》

↪Actually welcome to the Concept of the Oxidation states of an atom

↪Basically , before solving we know that ....

↪as a primary oxidation state, Na i.e sodium has a +1 oxidation state in its natural occurrence.

↪so taking "X" as the oxidation state of the oxygen we get as

↪2 (1) + 2 (X) = 0

↪so further , since there is no total charge on the compound, we equate it to Zero

↪=》 2 + 2X = 0

↪=》 2x = -2

↪=》 X = -1

〽so here the Oxidation state of the oxygen is -1