How to find oxidation stste of phosphorous in 3h3po4-?
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Given,
3H3P04-
So,
As we know the oxidation states of oxygen(O)=-2 and hydrogen(H)=+1
let the oxidation state of phosphorus(P) be "x"
so as per given compound,
3(+1) +3(x) + 4(-2)=-1
+3+3(x)-8=-1
3(x)=-1+8-3
3(x)=4
x=4/3
Therefore the oxidation state of phosphorus is 4/3
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