How to find perimeter of rhombus with diagonals 10 and 24?
Answers
Answered by
2
Hey !!
Here's your answer .. ⤵⤵
______________________
◻ABCD is a Rhombus.
DB and BC are diagonals of Rhombus ABCD.
DB = 10 unit
AC = 24 unit
Both diagonals interest each other at O at right angle.
OA = OC = 12 unit
OD = OB = 5 unit
In ∆ODC, angle DOC = 90°
OD² + OC² = DC²
5² + 12² = DC²
DC² = 25 + 144
DC² = 169
DC = √169
DC = 13 unit
DC = AB = BC = CD = 13 unit.
Perimeter of ABCD = AB + BC + CD + DA
= 13 + 13 + 13 + 13
= 52 unit
___________________________
Hope it helps..
Thanks :)
Here's your answer .. ⤵⤵
______________________
◻ABCD is a Rhombus.
DB and BC are diagonals of Rhombus ABCD.
DB = 10 unit
AC = 24 unit
Both diagonals interest each other at O at right angle.
OA = OC = 12 unit
OD = OB = 5 unit
In ∆ODC, angle DOC = 90°
OD² + OC² = DC²
5² + 12² = DC²
DC² = 25 + 144
DC² = 169
DC = √169
DC = 13 unit
DC = AB = BC = CD = 13 unit.
Perimeter of ABCD = AB + BC + CD + DA
= 13 + 13 + 13 + 13
= 52 unit
___________________________
Hope it helps..
Thanks :)
Attachments:
Similar questions