Math, asked by murugu1973, 9 months ago

How to find positive square root of surds

Answers

Answered by drsinghsayana

Answer:

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14 + 6√5

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2

***14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 23√5+ √5^2***

***14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 23√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2***

***14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 23√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2Hence***

***14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 23√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2Hence14+6√5 = ( 3+ √5)^2***

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 23√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2Hence14+6√5 = ( 3+ √5)^2Square root of 14 + 6√5 = square root of (3+√5)^2

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 23√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2Hence14+6√5 = ( 3+ √5)^2Square root of 14 + 6√5 = square root of (3+√5)^2Square root of 14 + 6√ 5 = 3 + √5

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 23√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2Hence14+6√5 = ( 3+ √5)^2Square root of 14 + 6√5 = square root of (3+√5)^2Square root of 14 + 6√ 5 = 3 + √5Ans : 3+√5..

good morning dude have a nice day..

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How to find positive square root of surds

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14 + 6√5

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 2*3*√5+ √5^2

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 2*3*√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 2*3*√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2Hence

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 2*3*√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2Hence14+6√5 = ( 3+ √5)^2

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 2*3*√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2Hence14+6√5 = ( 3+ √5)^2Square root of 14 + 6√5 = square root of (3+√5)^2

14 + 6√5= 9+ 5 + 6√5 ( splitting 14 as 9+5)= 3^2 + √5^2+ 6√5= 3^2 + 6√5 + √5^2= 3^2+ 2*3*√5+ √5^2= a^2 + 2ab+ b^2 = (a+b)^2Hence14+6√5 = ( 3+ √5)^2Square root of 14 + 6√5 = square root of (3+√5)^2Square root of 14 + 6√ 5 = 3 + √5