how to find potential of hydrogen electrode at pH=10 ????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????/???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answers
Answered by
1
to find potential formula is
Ecell = E° − 0.0591 log [H₂]
1 [H⁺]
⇒ for [H⁺]
pH = 10 so, or [H⁺] = 10∧⁻pH
pH = − log [H⁺] pH = 10
so [H⁺] = 10⁻¹⁰ [H⁺] = 10⁻¹⁰
⇒ E° = 0
⇒ [H₂] = 1 [1 atm]
Ecell = E° − 0.0591 log [H₂]
1 [H⁺]
= 0 − 0.0591 log [1]
1 [10⁻¹⁰ ]
= − 0.0591 (log 10¹⁰)
= − 0.0591 (10 log 10)
= − 0.0591 (10 * 1) {log 10 =1}
= − 0.0591 x 10
Ecell = − 0.59 V
Ecell = E° − 0.0591 log [H₂]
1 [H⁺]
⇒ for [H⁺]
pH = 10 so, or [H⁺] = 10∧⁻pH
pH = − log [H⁺] pH = 10
so [H⁺] = 10⁻¹⁰ [H⁺] = 10⁻¹⁰
⇒ E° = 0
⇒ [H₂] = 1 [1 atm]
Ecell = E° − 0.0591 log [H₂]
1 [H⁺]
= 0 − 0.0591 log [1]
1 [10⁻¹⁰ ]
= − 0.0591 (log 10¹⁰)
= − 0.0591 (10 log 10)
= − 0.0591 (10 * 1) {log 10 =1}
= − 0.0591 x 10
Ecell = − 0.59 V
Similar questions
Math,
7 months ago
Math,
7 months ago
Hindi,
7 months ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago
English,
1 year ago
Environmental Sciences,
1 year ago