Question

How to find rational number between two fractions?

Answer 1

hii!!

here's ur answer...

if u want to find rational numbers between two fraction then follow the following examples.

$1.let \: the \: two \: fractions \: be \: \frac{4}{5} and \frac{1}{5} . \\ \\ here \: u \: can \: simply \: tell \: there \: are \: 2 \: rational \: \\ numbers \: between \: them \: as \: their \:denominator \\ are \: same \: and \: the \: two\: rational \: numbers \\ between \: them \: are \: \frac{3}{5} and \frac{2}{5} . \\ \\ but \: if \: its \: asked \: to \: find \: 5 \: or \: more \: rational \: \\ numbers \: between \: them \: then \: u \: have \: to \: \\ multiply both \: the \: fractions. \\ \\ like \: we \: have \: to \: find \: 5 \: rational \: numbers \: between \: \\ \frac{4}{5} and \frac{1}{5} \\ then \: we \: will \: multiply \: both \: the \: fractions \\ \: by \: 5. the \: more \: greater \: number \: u \: will \: \\ multiply \: both \: the \: fractions \: the \: more \: rational \: \\ number \: u \: will \:get. \\ \\ now \\ \: \: \: \: \: \: \frac{4 \times 5}{5 \times 5} = \frac{20}{25} \\ \\ \: \: \: \: \: \: \frac{1 \times 5}{5 \times 5} = \frac{5}{25} \\ \\ now \: we \: can \: simply \: find \: many \: rational \: \\ numbers \: which \: are \: \frac{6}{25} \: \: \frac{7}{25} \: \: \frac{8}{25} \: \: \frac{9}{25} \: \: \frac{10}{25} \\ \\ \frac{11}{25} \: \: \frac{12}{25} \: \: \frac{13}{25} \: \: \frac{14}{25} \: \: \frac{15}{25} \: \: \frac{16}{25} \: \: \frac{17}{25} \: \: \frac{18}{25} \: and\frac{19}{25} . \\ \\ and \: make \: it \: sure \: that \: all \: denominator \: of \: \\ all \: the \: fractions \: should \: be \: same. \\ \\ 2. \: we \: have \: to \: find \: 3 \: rational \: numbers \: \\ between \: \frac{2}{3} and \: \frac{6}{7} do \: not \: get \: confused \: and \\ \: write \: that \: the \: rational \: numbers \: between \: \\ them \: are \: \frac{3}{3} or \: \frac{5}{7} . i \: told \: u \: that \: if \: their \: \\ denminator \: are \: same \: then \: only \: we \: can \: find. \\ \\ so \: first \: we \: have \: to \: make \: their \: denominator \: \\ same. \: for \: that \: we \: have \: to \: find \: lcm \: of \: both \: the \: \\ denominator. \\ \\ lcm \: of \: 3 \: and \: 7 \: is = 3 \times 7 \: (as \: they \: are \: prime \: \\ numbers \: and \: they \: cannot \: be \: multiplied \: by \: any \\ other \: number) \: so \: lcm \: is \: = 21 \\ \\ now \: we \: will \: multiply \: 2 \: by \: 7 \: and \: 6 \: by \: 2. \\ \\ now \: their \: fractions \: will \: be \: \frac{14}{21} and \: \frac{12}{21} \\ still \: there \: is \: only \: one \: rational \: number \: \\ between \: them \: so \: now \: we \: will \: multiply \: both \: \\ the \: fractions by \: 2. \\ \\ = \frac{14 \times 2}{21 \times 2} = \frac{28}{42} \\ \\ = \frac{12 \times 2}{21 \times 2} = \frac{24}{42} \\ \\ now \: the \: three \: rational \: numbers \: between \: \\ them \: are \: \frac{25}{42} \: \: \frac{26}{42} \: and \: \frac{27}{42} . \\ \\ hope \: u \: understood \: how \: to \: find \: rational \: numbers \: \\ between \: two \: fractions. \\ \\ hope \: this \: helps...$

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