how to find refractive index of air?
Answers
Answer:
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Explanation:
Thus we define the refractive index of air n = 1 + k p, where p is the air pressure and k is an unknown constant. When the pressure is changed, the change in the refraction index is ∆n = k ∆p.
Answer:
The refractive index formula is given as follows:
n =
c
v
where,
n = refractive index of the medium
c = speed of light when in vacuum
v = speed of light when in medium
Refractive Index Formula Derivation
First off all, one must apply the Snell’s law as follows:
For a ray which goes from the air to a medium
Nasin i = nmsin r
Here nm refers to the refractive index of the medium
Na refers to the refractive index of air
i refers to the angle of incidence
r refers to the angle of refraction
Now one must nm the subject of the above equation
Nm =
n
a
s
i
n
i
s
i
n
r
Also, na = 1
Nm =
s
i
n
i
s
i
n
r
Above all, nm =
c
v
=
s
p
e
e
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f
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i
g
h
t
i
n
t
h
e
v
a
c
u
u
m
s
p
e
e
d
o
f
l
i
g
h
t
i
n
t
h
e
m
e
d
i
u
m
Solved Questions on Resistivity Formula
Q1. A ray of light is transient through a medium to another medium. The angle of the incident comes out to be 30 degrees. Also, the angle of refraction happens to be 50 degrees. Find out the refractive index of the second medium?
Answer: The parameters which are known are:
Angle of incidence (‘i’) = 30 degrees
Angle of refraction (‘r’) = 50 degrees
The refractive index formula is as follows
n =
s
i
n
i
s
i
n
r
n =
s
i
n
30
s
i
n
50
Finally, n =
0.5
0.766
= 0.6527
Q2. Find out the refractive index of the medium such that the speed of light in the medium is 2 × 108 m/s?
Answer: The information we have is,
Speed of light in the medium(‘v’) = 2×108m/s
Speed of light in the vacuum(‘c’) = 3×108m/s
Now, one must apply the formula of refractive index,
So, n =
c
v
n =
3
×
108
2
×
108
n = 1.5