Math, asked by anaskhan3, 1 year ago

how to find root 1800 orignal no i mean how to solve


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anaskhan3: please hindi

Answers

Answered by satyasaigopal2002
0
[tex] \sqrt{1800} = \sqrt{9*200} = \sqrt{( 3^{2})*200} = 3\sqrt{2*100} =30 \sqrt{2} =[/tex]
=42.46 approx

anaskhan3: no sir
satyasaigopal2002: then what you want
anaskhan3: yes
anaskhan3: 30 root 2 is
satyasaigopal2002: 30X1.414=42.46......
rakeshmohata: чup thє vαluє σf √2 = 1.414
Answered by rakeshmohata
0
ѕquαrє rσσt σf αnч íntєgєr mєαnѕ thαt σnє tєrm tσ fínd σut whích íѕ whєn multíplíєd вч ítѕєlf gívєѕ thє fσrmєr íntєgєr..

thuѕ tσ fínd α rσσt σf αnч numвєr ..trч tσ вrєαk ít σut σr єlѕє tαkє σut thє lcm.

fσr 1800,
numвєrѕ multíplíєd αrє : 3×3×2×2×2×5×5

thuѕ thє twσ ѕímílαr tєrmѕ αrє tαkєn αѕ σnє αnd multíplíєd вч thє lєft σvєrѕ..

hєrє 3 ,2,5 cαmє twícє..whєrєαѕ thєrє íѕ αn єхtrα 2 thσugh..
ѕσ ut gσєѕ líkє..

3×2×5×√2 ..αѕ √2×√2 =2.

ѕσ thє rєquírєd αnѕwєr íѕ 3×2×5×√2 =30√2

hσpє u gσt ít.
prσud tσ hєlp u..
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