How to find roots when the quadratic equation are reciprocal of each other
Answers
Answer:
Step-by-step explanation:
What happens if the roots of a quadratic equation are reciprocal of the roots of another quadratic eqUATION
Yeah I know, you wanted to know the relation between the coefficients of the two quadratic equations….
Let us take a quadratic equation ax2+bx+c=0. Let its roots be α,β.
We have α+β=−ba and αβ=ca.
Let us call the above as fact(1)
We want a quadratic equation with reciprocal roots, i.e. 1α,1β.
To form that quadratic equation let us find the sum and product of the ‘new’ roots using fact(1) :
1α+1β=α+βαβ=−bc
Likewise
1α∗1β=1αβ=ac
Now to write the required quadratic equation using
x2− (sum of roots)x+ (product of roots) = 0
x2+bcx+ac=0
Rearranging we get cx2+bx+a=0.
If ax2+bx+c=0, has roots α,β, then cx2+bx+a=0 will have roots 1α,1β.
The coefficient of x2 and the constant term are interchanged, but the coefficient of x remains the same.
Hope that was helpful,
Cheers