Question

how to find sin 45 degree

Answer 1

Hiii friend,


Let ∆ABC is a right angled triangle. Right angled at B and Angle A = 45°.


Angle A = 45°


And,


Angle B = 90°


Therefore,


AngleC = 180° - (A+B)

Angle C = 180°(45°+90°) = 45°.


Angle A = Angle C ( Each equal 45°)


Therefore,


BC = AB ( Sides opposite to equal angles are equal).


Let BC = AB = a

Therefore,

By pythagoras theroem,


(AC)² = (AB)² + (BC)²


AC² = a² + a² = 2a²


AC = ✓2a² = ✓2 a


Therefore,


Sin45° = Perpendicular/Hypotenuse = BC/AC = a/✓2 a = 1/✓2


Hence

Sin45° = 1/✓2

HOPE IT WILL HELP YOU.... :-)

Answer 2

Heyaa.....!!
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you can find sin 45° in the trigonometery table.