Question

How to find smallest square number which is divisible by 6 9 and 15?

Answer 1

Hey there!

Since, we wanted smallest perfect square number divisible by 6, 9 and 15.
So, we calculated LCM by prime factorisation.

LCM = 90

But, 2 and 5 are not in pair.
Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).
= 90 × 2 × 5
= 90 × 10
= 900

Hence,
Required smallest square no. that's divisible by 6, 9 and 15 = 900
SOLUTION IN THE ABOVE PIC. IS ALSO FOR REFERENCE

Hope it helped
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Answer 2

We'll calculate LCM

LCM (6, 9, 15) = 90
2 and 5 not occuring in pair form

But to make it a perfect square, multiply 2 and 5 to 90 (LCM)
90×2×5
900

Required smallest square number is 900

Hope it helped
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