how to find square root odd decimal number easily
Answers
Answered by
1
It is very easy first try to find it in the calculater then you will get it
subashM:
manually how in the exam
Answered by
4
it is easy to find a root number by using Vedic mathematics.
Ex:-
![{86}^{2} {86}^{2}](https://tex.z-dn.net/?f=+%7B86%7D%5E%7B2%7D+)
step 1:- number's last number square = answer's last number
6×6 = 36
So root number's last number is 6 and 3 is in hand.
Step 2:- 6×8+ 6×8 = 48+48=96
96+In hand = 96+3=99
So the second number of answer is 9 and another 9 is in hand.
Step 3:- the last number's square
8×8=64
64+In hand =64+9=73
So the last number's of answer if 73
therefore the answer is 7396
hope it will help you. Plz mark this as a brianliest answer. THANK YOU....
Ex:-
step 1:- number's last number square = answer's last number
6×6 = 36
So root number's last number is 6 and 3 is in hand.
Step 2:- 6×8+ 6×8 = 48+48=96
96+In hand = 96+3=99
So the second number of answer is 9 and another 9 is in hand.
Step 3:- the last number's square
8×8=64
64+In hand =64+9=73
So the last number's of answer if 73
therefore the answer is 7396
hope it will help you. Plz mark this as a brianliest answer. THANK YOU....
Similar questions
Math,
9 months ago
English,
1 year ago
Math,
1 year ago
Math,
1 year ago
Social Sciences,
1 year ago