how to find tan R ???
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aniketjadhao270:
therefor pq=3 and tan R=3/4
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by Pythagoras theorem
PQ^2 + QR^2 = PR^2
PQ^2 + 4^2 = 5^2
PQ^2 = 25 - 16
PQ = √9 = 3
and tanR = PQ/QR
tanR = 3/4
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PQ^2 + QR^2 = PR^2
PQ^2 + 4^2 = 5^2
PQ^2 = 25 - 16
PQ = √9 = 3
and tanR = PQ/QR
tanR = 3/4
follow me
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