Question

How to find the area of a right angled isosceles triangle whose hypotenuse is 12 cm and angle is 90°?

Answer 1

Let , Triangle ABC is a triangle right angle at B.
and Length of AB be x cm.
But it is given that triangle ABC is an isosceles triangle.
So, AB = BC = x cm.

Now, In triangle ABC
By Pythagoras Theoram,
(AC) square = (AB)square +(BC)square.
(12) square = (x)square + (x)square
144 = (2x)square
(x)square = 144/2
(x) square = 72
x = 6root2

So, AB = BC = x = 6root2

Therefore,
Area of triangle = 1/2 × AB × BC
= 1/2 × 6root2 × 6root2
= 3 × 6 × 2
= 36 cm square.

HOPE THIS WILL HELP YOU.