how to find the area of regular octagon with side 10cm?
manoj1138:
if u say that its sides r of 10cm then the octagon cannot be irregular
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2
side a=10cm. Now the area of an octagon formua is 2*a^2*(1+_/2) =2*10^2*(1+_/2) =2*100*(1+_/2) =200*(1+_/2)
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In a regular octagon , 8 equilateral triangles with side 8cm can be drawn. So area of octagon = 8 × area of triangles.
side = 10cm
Area = 8✓3/4 × 10² ( area of equilateral triangle =✓3/4 × a²)
= 8✓3/4×100
= 8✓3×25
=200✓3 cm²
side = 10cm
Area = 8✓3/4 × 10² ( area of equilateral triangle =✓3/4 × a²)
= 8✓3/4×100
= 8✓3×25
=200✓3 cm²
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