Question

How to find the area of square whose diagonal = 5.2 cm

Answer 1

$\bf \large \it \: Hey \: User!!!$

given the diagonal of the square = 5.2cm

we know that all sides of a square are equal and they make a right angle each side.

therefore by Pythagoras theorem we get :-

diagonal² = side² + side² (according to square)
>> (5.2)² = 2side²
>> 27.04 = 2side²
>> 27.04/2 = side²
>> 13.54 = side²
>> side = √13.54
>> side = 3.67cm (approximately)

$\bf \large \it{Cheers!!!}$

Answer 2

Hello!

$\star \: \sf D = 5.2\:cm$

Then,

$\underline{\bf{For \:Square}}$ :

$\sf D^{2} = \sf side^{2} + side^{2} \\ \\ \implies \sf D^{2} = \sf 2side^{2} \\ \\ \implies \sf side^{2} = \dfrac{\sf D^{2}}{2} \\ \\ \implies \sf side^{2} = \dfrac{(5.2)^{2}}{2} \\ \\ \implies \sf side^{2} = \dfrac{27.04}{2} \\ \\ \implies \sf side = \sqrt{13.52} \implies \sf side = \boxed{\red{\bf{3.67\:cm}}}$

Cheers!