how to find the axes of symmetry?
Answers
Answered by
1
For any quadratic equation the axis of symmetry will be this:
x=-b/2a
For example:
x^2+6x+13 A=1 B=6 C=13
Axis of Symmetry equation x=-b/2a
x=-6/2(1)
x=-3
So the axis of symmetry for this equation would be a line at x= negative 3. Hope this helps. Post with additional details if it still doesn't make sense!!!
x=-b/2a
For example:
x^2+6x+13 A=1 B=6 C=13
Axis of Symmetry equation x=-b/2a
x=-6/2(1)
x=-3
So the axis of symmetry for this equation would be a line at x= negative 3. Hope this helps. Post with additional details if it still doesn't make sense!!!
Similar questions