Question

How to find the decimal number for √8. (e.g., √1 = 1.41).

Need the method.​

Answer 1

Answer:

$\sqrt{8 \: = } \sqrt{4 \times2} \\ = \sqrt{2 {}^{2} } \times \sqrt{2} \\ = 2 \times \sqrt{2} \\ = \sqrt[2]{2}$

here comes ur answer

Answer 2

Answer:

11.28 maybe (ー_ー)

Step-by-step explanation:

=8×1.41

= 11.28